Difference between revisions of "Perceptron"
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* The weights and threshold may be chosen so that the function is [[:Category:balanced function | balanced]]. | * The weights and threshold may be chosen so that the function is [[:Category:balanced function | balanced]]. | ||
* The perceptron is a special case of the [[polynomial threshold]] function. | * The perceptron is a special case of the [[polynomial threshold]] function. | ||
+ | * A perceptron has [[nearest neighbor representation|nearest neighbor]] complexity equal to <math>NN(f) = 2</math>. However, the Boolean nearest-neighbor complexity <math>BNN(f)</math> can be high, e.g for the perceptron with all weights equal and <math>t = n/3</math>, then <math>2^{\Omega(n)}</math> markers are required. <ref>Péter Hajnal, Zhihao Liu, György Turán, [https://arxiv.org/pdf/2004.01741.pdf Nearest neighbor representations of Boolean functions], Theorem 4</ref> | ||
* TODO | * TODO | ||
Revision as of 09:23, 28 October 2020
Definition
Let [math]n[/math] be a positive integer and let [math]t, \{w_i\}_{i=1}^n[/math] be real numbers. The perceptron function, or linear threshold function [math]f:\{-1,1\}^n \to \{-1,1\}[/math] with weights [math]w_i[/math] and threshold [math]t[/math] is defined as
[math] f(x) = \begin{cases} 1, & \text{if} ~ \sum_i w_i x_i \geq t \\ -1 & \text{otherwise} \end{cases}[/math]
The majority function is a special case of the perceptron, with threshold [math]t=0[/math] and all weights [math]w_i[/math] equal to each other.
Properties
- If all weights are equal to each other, the function is symmetric.
- If all weights are non-negative, or all weights are non-positive, the function is monotone.
- The weights and threshold may be chosen so that the function is balanced.
- The perceptron is a special case of the polynomial threshold function.
- A perceptron has nearest neighbor complexity equal to [math]NN(f) = 2[/math]. However, the Boolean nearest-neighbor complexity [math]BNN(f)[/math] can be high, e.g for the perceptron with all weights equal and [math]t = n/3[/math], then [math]2^{\Omega(n)}[/math] markers are required. [1]
- TODO
References
- ↑ Péter Hajnal, Zhihao Liu, György Turán, Nearest neighbor representations of Boolean functions, Theorem 4